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| /**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
unordered_map<int, int> umap;
TreeNode* build(vector<int>& preorder, vector<int>& inorder, int l1, int r1, int l2, int r2) {
if (l1 > r1) return nullptr;
int len = umap[preorder[l1]] - l2;
TreeNode* root = new TreeNode(preorder[l1]);
root->left = build(preorder, inorder, l1 + 1, l1 + len, l2, l2 + len - 1);
root->right = build(preorder, inorder, l1 + len + 1, r1, l2 + len + 1, r2);
return root;
}
TreeNode* buildTree(vector<int>& preorder, vector<int>& inorder) {
for (int i = 0; i < inorder.size(); i ++) {
umap[inorder[i]] = i;
}
return build(preorder, inorder, 0, preorder.size() - 1, 0, inorder.size() - 1);
}
};
|